🎰 Blackjack - Wikipedia

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I will assume some basic familiarity with the game of Blackjack, but The same logic holds true if the dealer is showing a 5, just that there is.


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I will assume some basic familiarity with the game of Blackjack, but The same logic holds true if the dealer is showing a 5, just that there is.


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blackjack game logic

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It is a comparing card game between one or more players and a dealer, where each player in turn competes against the dealer. Players do not compete against​.


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almarehotel.ru β€Ί blackjack-strategy-charts.


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One will deal with data manipulation and logic, and the other will perform the UI functions, such as drawing the cards onto the screen and such. BlackJack game​.


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The game will be a simplified version of Blackjack as it is played in a casino. The computer will act as the dealer. As in the previous exercise, your program will.


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Note that only one ace can count as 11 in a hand. (Otherwise, the total will be at least ) Calculate hand with all aces counting 1 if ((hand.


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The game will be a simplified version of Blackjack as it is played in a casino. The computer will act as the dealer. As in the previous exercise, your program will.


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blackjack game logic

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One will deal with data manipulation and logic, and the other will perform the UI functions, such as drawing the cards onto the screen and such. BlackJack game​.


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After you generate this list of possibilities, you can then see which possibility has the least number of cards to create the blackjack or highest hand value, and choose that possibility. Feedback post: New moderator reinstatement and appeal process revisions. See stackoverflow. However, I just got to the point of adding together the score after each hand something I thought would be easy but Aces are proving to rack my brain endlessly. I am coding a blackjack game and I am very far through. Thanks so much for the help. Featured on Meta. Sign up using Email and Password. Logic for Blackjack Game Ask Question. How do I make a loop to go through an ArrayList of Integers called Hand which has ints which correspond to the cards that are in the hand. I ask on SO as someone may have a clever method for answering this type of problem. Post as a guest Name. Note that only one ace can count as 11 in a hand. Otherwise, the total will be at least Only one ace can ever be Marcel Duran Marcel Duran 16 2 2 bronze badges. I apologize for my subject line being so poor, if someone could edit it to: "How to count values in an ArrayList which can either be one number or another - Blackjack Game". If not, continue. Hatefiend Hatefiend 2, 3 3 gold badges 17 17 silver badges 47 47 bronze badges. Kevin Hou Kevin Hou 1. Question feed. Related 0. That's a very broad question for this site, and will require substantial effort for someone to answer. How Stack Overflow hires engineers. I've never encountered a situation where numbers in my array can either be an 11 or a 1. Sign up using Facebook. Hot Network Questions. Since casinos play with multiple decks, it's possible to get up to 21 aces in the same hand mathematically. Viewed times. New post lock available on meta sites: Policy Lock. A player hits and now has a Ace, a 5, a 2, a King, and now draws an Ace.

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If it is exactly 21, add that hand to your successes, and stop hitting. If your sum is greater than 21, you bust. In a real blackjack game, you might also want to return the fact of whether the blackjack game logic total is soft or hard also. Email Required, but never shown.

It's a common algorithm problem and there are probably very efficient solutions out there for you to look at. Active 4 years, 3 months ago. Stack Overflow works best blackjack game logic JavaScript enabled.

Sign up or log in Sign up using Google. I understand it's a bit off the norm for questions but honestly I don't know if I can ask it any more succinctly. Active Oldest Votes. Learn more. The arraylist to represent his hand is [1, 10, 2, 5, 1]. Take the sum of your "Hand" ArrayList, for any location that you see an "Ace" at, calculate that sum with both 1 or 11 as the additive. The brute force method of solving this problem is to implement a "look-ahead" function, where you can look at your entire hand once, then calculate all the possible combinations your hand provides, including the Aces within your hand as either 1's or 11's. Asked 5 years, 3 months ago. The Overflow Blog.